(3+2i)+(4+bi)=(7-5i)

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Solution for (3+2i)+(4+bi)=(7-5i) equation:


Simplifying
(3 + 2i) + (4 + bi) = (7 + -5i)

Remove parenthesis around (3 + 2i)
3 + 2i + (4 + bi) = (7 + -5i)

Remove parenthesis around (4 + bi)
3 + 2i + 4 + bi = (7 + -5i)

Reorder the terms:
3 + 4 + bi + 2i = (7 + -5i)

Combine like terms: 3 + 4 = 7
7 + bi + 2i = (7 + -5i)

Remove parenthesis around (7 + -5i)
7 + bi + 2i = 7 + -5i

Add '-7' to each side of the equation.
7 + bi + -7 + 2i = 7 + -7 + -5i

Reorder the terms:
7 + -7 + bi + 2i = 7 + -7 + -5i

Combine like terms: 7 + -7 = 0
0 + bi + 2i = 7 + -7 + -5i
bi + 2i = 7 + -7 + -5i

Combine like terms: 7 + -7 = 0
bi + 2i = 0 + -5i
bi + 2i = -5i

Solving
bi + 2i = -5i

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2i' to each side of the equation.
bi + 2i + -2i = -5i + -2i

Combine like terms: 2i + -2i = 0
bi + 0 = -5i + -2i
bi = -5i + -2i

Combine like terms: -5i + -2i = -7i
bi = -7i

Divide each side by 'i'.
b = -7

Simplifying
b = -7

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