(3*1)+(3*2y)=y+2y+4y

Solution for (3*1)+(3*2y)=y+2y+4y equation:

Simplifying
(3 * 1) + (3 * 2y) = y + 2y + 4y

Multiply 3 * 1
(3) + (3 * 2y) = y + 2y + 4y
3 + (3 * 2y) = y + 2y + 4y

Multiply 3 * 2
3 + (6y) = y + 2y + 4y

Combine like terms: y + 2y = 3y
3 + (6y) = 3y + 4y

Combine like terms: 3y + 4y = 7y
3 + (6y) = 7y

Solving
3 + (6y) = 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
3 + (6y) + -7y = 7y + -7y

Combine like terms: (6y) + -7y = -1y
3 + -1y = 7y + -7y

Combine like terms: 7y + -7y = 0
3 + -1y = 0

Add '-3' to each side of the equation.
3 + -3 + -1y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 0 + -3
-1y = 0 + -3

Combine like terms: 0 + -3 = -3
-1y = -3

Divide each side by '-1'.
y = 3

Simplifying
y = 3