(3)3z+9+14z=4z+5

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Solution for (3)3z+9+14z=4z+5 equation: 



(3)3z+9+14z=4z+5

We move all terms to the left:

(3)3z+9+14z-(4z+5)=0

We add all the numbers together, and all the variables

47z-(4z+5)+9=0

We get rid of parentheses

47z-4z-5+9=0

We add all the numbers together, and all the variables

43z+4=0

We move all terms containing z to the left, all other terms to the right

43z=-4

z=-4/43

z=-4/43

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