(3)2/3(3x+14)=7x+6(3)

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Solution for (3)2/3(3x+14)=7x+6(3) equation: 



(3)2/3(3x+14)=7x+6(3)

We move all terms to the left:

(3)2/3(3x+14)-(7x+6(3))=0



Domain of the equation: 3(3x+14)!=0

x∈R



We get rid of parentheses

32/3(3x+14)-7x-63=0

We multiply all the terms by the denominator


-7x*3(3x+14)-63*3(3x+14)+32=0

Wy multiply elements

-21x^2(3-189x(3+32=0

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