(3)/(35)=(y+2)/(112)

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Solution for (3)/(35)=(y+2)/(112) equation: 



(3)/(35)=(y+2)/(112)

We move all terms to the left:

(3)/(35)-((y+2)/(112))=0

We calculate fractions


(-((y+2)*35)/()+()/()=0



We calculate terms in parentheses: +(-((y+2)*35)/()+()/(), so:

-((y+2)*35)/()+()/(

We add all the numbers together, and all the variables

-((y+2)*35)/()+1

We multiply all the terms by the denominator


-((y+2)*35)+1*()



We calculate terms in parentheses: -((y+2)*35), so:

(y+2)*35

We multiply parentheses

35y+70

Back to the equation:

-(35y+70)



We add all the numbers together, and all the variables

-(35y+70)

We get rid of parentheses

-35y-70

Back to the equation:

+(-35y-70)



We get rid of parentheses

-35y-70=0

We move all terms containing y to the left, all other terms to the right

-35y=70

y=70/-35

y=-2

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