(3)/(2)(12-2x)-4=5x+2(x-7)2

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Solution for (3)/(2)(12-2x)-4=5x+2(x-7)2 equation: 



(3)/(2)(12-2x)-4=5x+2(x-7)2

We move all terms to the left:

(3)/(2)(12-2x)-4-(5x+2(x-7)2)=0



Domain of the equation: 2(12-2x)!=0

x∈R



We add all the numbers together, and all the variables

3/2(-2x+12)-(5x+2(x-7)2)-4=0

We multiply all the terms by the denominator


-((5x+2(x-7)2))*2(-2x+12)-4*2(-2x+12)+3=0



We calculate terms in parentheses: -((5x+2(x-7)2))*2(-2x+12), so:

(5x+2(x-7)2))*2(-2x+12

We add all the numbers together, and all the variables

-2x+(5x+2(x-7)2))*2(+12

Back to the equation:

-(-2x+(5x+2(x-7)2))*2(+12)



We add all the numbers together, and all the variables

-(-2x+(5x+2(x-7)2))*212-4*2(-2x+12)+3=0

Wy multiply elements

-(-2x+(5x+2(x-7)2))*212-8x(-+3=0

We use the square of the difference formula

-(-2x+(5x+2(x-7)2))*212-8x(-3=0

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