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(3(m+5))=(4(2m))
We move all terms to the left:
(3(m+5))-((4(2m)))=0
determiningTheFunctionDomain (3(m+5))-(42m)=0
We add all the numbers together, and all the variables
(3(m+5))-(+42m)=0
We get rid of parentheses
(3(m+5))-42m=0
We calculate terms in parentheses: +(3(m+5)), so:We add all the numbers together, and all the variables
3(m+5)
We multiply parentheses
3m+15
Back to the equation:
+(3m+15)
-42m+(3m+15)=0
We get rid of parentheses
-42m+3m+15=0
We add all the numbers together, and all the variables
-39m+15=0
We move all terms containing m to the left, all other terms to the right
-39m=-15
m=-15/-39
m=5/13
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