(3(6)2)v+10=33v+10

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Solution for (3(6)2)v+10=33v+10 equation: 



(3(6)2)v+10=33v+10

We move all terms to the left:

(3(6)2)v+10-(33v+10)=0

determiningTheFunctionDomain
362v-(33v+10)+10=0

We get rid of parentheses

362v-33v-10+10=0

We add all the numbers together, and all the variables

329v=0

v=0/329

v=0

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