(3(2y+4))/14=1

Solution for (3(2y+4))/14=1 equation:

(3(2y+4))/14=1

We move all terms to the left:

(3(2y+4))/14-(1)=0

We multiply all the terms by the denominator


(3(2y+4))-1*14=0


We calculate terms in parentheses: +(3(2y+4)), so:

3(2y+4)

We multiply parentheses

6y+12

Back to the equation:

+(6y+12)


We add all the numbers together, and all the variables

(6y+12)-14=0

We get rid of parentheses

6y+12-14=0

We add all the numbers together, and all the variables

6y-2=0

We move all terms containing y to the left, all other terms to the right

6y=2

y=2/6

y=1/3