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(3(2x+3)/13=2x-7
We move all terms to the left:
(3(2x+3)/13-(2x-7)=0
Domain of the equation: 13-(2x-7)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(2x-7)!=-13
x∈R
(3(2x+3)=0
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