(3(-2y+30)+6)+(2y+10)=4(-2y+30)+(4y-14)

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Solution for (3(-2y+30)+6)+(2y+10)=4(-2y+30)+(4y-14) equation: 



(3(-2y+30)+6)+(2y+10)=4(-2y+30)+(4y-14)

We move all terms to the left:

(3(-2y+30)+6)+(2y+10)-(4(-2y+30)+(4y-14))=0

We get rid of parentheses

(3(-2y+30)+6)+2y-(4(-2y+30)+(4y-14))+10=0



We calculate terms in parentheses: +(3(-2y+30)+6), so:

3(-2y+30)+6

We multiply parentheses

-6y+90+6

We add all the numbers together, and all the variables

-6y+96

Back to the equation:

+(-6y+96)





We calculate terms in parentheses: -(4(-2y+30)+(4y-14)), so:

4(-2y+30)+(4y-14)

We multiply parentheses

-8y+(4y-14)+120

We get rid of parentheses

-8y+4y-14+120

We add all the numbers together, and all the variables

-4y+106

Back to the equation:

-(-4y+106)



We add all the numbers together, and all the variables

2y+(-6y+96)-(-4y+106)+10=0

We get rid of parentheses

2y-6y+4y+96-106+10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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