(2z/z)+3=(3/z-10)+2

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Solution for (2z/z)+3=(3/z-10)+2 equation: 



(2z/z)+3=(3/z-10)+2

We move all terms to the left:

(2z/z)+3-((3/z-10)+2)=0



Domain of the equation: z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: z-10)+2)!=0

z∈R



We add all the numbers together, and all the variables

(+2z/z)-((3/z-10)+2)+3=0

We get rid of parentheses

2z/z-((3/z-10)+2)+3=0

We calculate fractions


2z^2/z^2+(-((3*z)/z^2+3=0

We add all the numbers together, and all the variables

2z^2/z^2+(-((+3z)/z^2+3=0

We calculate fractions

We do not support ezpression: z^4

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