(2z-(10z+6))=6+(7z+0)

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Solution for (2z-(10z+6))=6+(7z+0) equation:


Simplifying
(2z + -1(10z + 6)) = 6 + (7z + 0)

Reorder the terms:
(2z + -1(6 + 10z)) = 6 + (7z + 0)
(2z + (6 * -1 + 10z * -1)) = 6 + (7z + 0)
(2z + (-6 + -10z)) = 6 + (7z + 0)

Reorder the terms:
(-6 + 2z + -10z) = 6 + (7z + 0)

Combine like terms: 2z + -10z = -8z
(-6 + -8z) = 6 + (7z + 0)

Remove parenthesis around (-6 + -8z)
-6 + -8z = 6 + (7z + 0)

Reorder the terms:
-6 + -8z = 6 + (0 + 7z)
Remove the zero:
-6 + -8z = 6 + (7z)
-6 + -8z = 6 + (7z)

Solving
-6 + -8z = 6 + (7z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-7z)' to each side of the equation.
-6 + -8z + (-7z) = 6 + (7z) + (-7z)

Combine like terms: -8z + (-7z) = -15z
-6 + -15z = 6 + (7z) + (-7z)

Combine like terms: (7z) + (-7z) = 0
-6 + -15z = 6 + 0
-6 + -15z = 6

Add '6' to each side of the equation.
-6 + 6 + -15z = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -15z = 6 + 6
-15z = 6 + 6

Combine like terms: 6 + 6 = 12
-15z = 12

Divide each side by '-15'.
z = -0.8

Simplifying
z = -0.8

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