(2z+6)+(4z-3)=(5z+12

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Solution for (2z+6)+(4z-3)=(5z+12 equation: 



(2z+6)+(4z-3)=(5z+12

We move all terms to the left:

(2z+6)+(4z-3)-((5z+12)=0

We get rid of parentheses

2z+4z-((5z+12)+6-3=0

We add all the numbers together, and all the variables

6z-((5z+12)+6-3=0

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