(2z+5)(z-3)=(z-6)(2z-2)-1

Solution for (2z+5)(z-3)=(z-6)(2z-2)-1 equation:

(2z+5)(z-3)=(z-6)(2z-2)-1

We move all terms to the left:

(2z+5)(z-3)-((z-6)(2z-2)-1)=0

We multiply parentheses ..

(+2z^2-6z+5z-15)-((z-6)(2z-2)-1)=0


We calculate terms in parentheses: -((z-6)(2z-2)-1), so:

(z-6)(2z-2)-1

We multiply parentheses ..

(+2z^2-2z-12z+12)-1

We get rid of parentheses

2z^2-2z-12z+12-1

We add all the numbers together, and all the variables

2z^2-14z+11

Back to the equation:

-(2z^2-14z+11)


We get rid of parentheses

2z^2-2z^2-6z+5z+14z-15-11=0

We add all the numbers together, and all the variables

13z-26=0

We move all terms containing z to the left, all other terms to the right

13z=26

z=26/13

z=2