(2z+3/3)+(3z-4/6)=(z-2/2)

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Solution for (2z+3/3)+(3z-4/6)=(z-2/2) equation: 


z in (-oo:+oo)

2*z+3*z+3/3-(4/6) = z-(2/2) // - z-(2/2)

2*z+3*z-z+3/3-(4/6)+2/2 = 0

2*z+3*z-z+3/3-2/3+2/2 = 0

4*z+4/3 = 0 // - 4/3

4*z = -4/3 // : 4

z = -4/3/4

z = -1/3

z = -1/3

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