(2z+3)/3+(3z-4)/6=(z-2)

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Solution for (2z+3)/3+(3z-4)/6=(z-2) equation: 


z in (-oo:+oo)

(2*z+3)/3+(3*z-4)/6 = z-2 // - z-2

(2*z+3)/3+(3*z-4)/6-z+2 = 0

(6*(2*z+3))/(3*6)+(3*(3*z-4))/(3*6)+(3*6*(-z))/(3*6)+(2*3*6)/(3*6) = 0

6*(2*z+3)+3*(3*z-4)+3*6*(-z)+2*3*6 = 0

21*z-18*z+6+36 = 0

3*z+6+36 = 0

3*z+42 = 0

(3*z+42)/(3*6) = 0

(3*z+42)/(3*6) = 0 // * 3*6

3*z+42 = 0

3*z+42 = 0 // - 42

3*z = -42 // : 3

z = -42/3

z = -14

z = -14

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