(2z+2)(2z-2)=

Solution for (2z+2)(2z-2)= equation:

Simplifying
(2z + 2)(2z + -2) = 0

Reorder the terms:
(2 + 2z)(2z + -2) = 0

Reorder the terms:
(2 + 2z)(-2 + 2z) = 0

Multiply (2 + 2z) * (-2 + 2z)
(2(-2 + 2z) + 2z * (-2 + 2z)) = 0
((-2 * 2 + 2z * 2) + 2z * (-2 + 2z)) = 0
((-4 + 4z) + 2z * (-2 + 2z)) = 0
(-4 + 4z + (-2 * 2z + 2z * 2z)) = 0
(-4 + 4z + (-4z + 4z2)) = 0

Combine like terms: 4z + -4z = 0
(-4 + 0 + 4z2) = 0
(-4 + 4z2) = 0

Solving
-4 + 4z2 = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4z2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4z2 = 0 + 4
4z2 = 0 + 4

Combine like terms: 0 + 4 = 4
4z2 = 4

Divide each side by '4'.
z2 = 1

Simplifying
z2 = 1

Take the square root of each side:
z = {-1, 1}