(2y-5)-8=(3y-y)+2

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Solution for (2y-5)-8=(3y-y)+2 equation: 



(2y-5)-8=(3y-y)+2

We move all terms to the left:

(2y-5)-8-((3y-y)+2)=0

We add all the numbers together, and all the variables

(2y-5)-((+2y)+2)-8=0

We get rid of parentheses

2y-((+2y)+2)-5-8=0



We calculate terms in parentheses: -((+2y)+2), so:

(+2y)+2

We get rid of parentheses

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

2y-(2y+2)-13=0

We get rid of parentheses

2y-2y-2-13=0

We add all the numbers together, and all the variables

-15!=0

There is no solution for this equation

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