(2y-4)*8y=16

Solution for (2y-4)*8y=16 equation:

(2y-4)*8y=16

We move all terms to the left:

(2y-4)*8y-(16)=0

We multiply parentheses

16y^2-32y-16=0

a = 16; b = -32; c = -16;
Δ = b2-4ac
Δ = -322-4·16·(-16)
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32\sqrt{2}}{2*16}=\frac{32-32\sqrt{2}}{32}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32\sqrt{2}}{2*16}=\frac{32+32\sqrt{2}}{32}
$