(2y-3)2-2(y+1)2+7=0

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Solution for (2y-3)2-2(y+1)2+7=0 equation:


Simplifying
(2y + -3) * 2 + -2(y + 1) * 2 + 7 = 0

Reorder the terms:
(-3 + 2y) * 2 + -2(y + 1) * 2 + 7 = 0

Reorder the terms for easier multiplication:
2(-3 + 2y) + -2(y + 1) * 2 + 7 = 0
(-3 * 2 + 2y * 2) + -2(y + 1) * 2 + 7 = 0
(-6 + 4y) + -2(y + 1) * 2 + 7 = 0

Reorder the terms:
-6 + 4y + -2(1 + y) * 2 + 7 = 0

Reorder the terms for easier multiplication:
-6 + 4y + -2 * 2(1 + y) + 7 = 0

Multiply -2 * 2
-6 + 4y + -4(1 + y) + 7 = 0
-6 + 4y + (1 * -4 + y * -4) + 7 = 0
-6 + 4y + (-4 + -4y) + 7 = 0

Reorder the terms:
-6 + -4 + 7 + 4y + -4y = 0

Combine like terms: -6 + -4 = -10
-10 + 7 + 4y + -4y = 0

Combine like terms: -10 + 7 = -3
-3 + 4y + -4y = 0

Combine like terms: 4y + -4y = 0
-3 + 0 = 0
-3 = 0

Solving
-3 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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