(2y-3)/(y+3)=5/7

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Solution for (2y-3)/(y+3)=5/7 equation: 


D( y )

y+3 = 0

y+3 = 0

y+3 = 0

y+3 = 0 // - 3

y = -3

y in (-oo:-3) U (-3:+oo)

(2*y-3)/(y+3) = 5/7 // - 5/7

(2*y-3)/(y+3)-(5/7) = 0

(2*y-3)/(y+3)-5/7 = 0

(7*(2*y-3))/(7*(y+3))+(-5*(y+3))/(7*(y+3)) = 0

7*(2*y-3)-5*(y+3) = 0

9*y-36 = 0

(9*y-36)/(7*(y+3)) = 0

(9*y-36)/(7*(y+3)) = 0 // * 7*(y+3)

9*y-36 = 0

9*y-36 = 0 // + 36

9*y = 36 // : 9

y = 36/9

y = 4

y = 4

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