(2y-10)=(3y+5)

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Solution for (2y-10)=(3y+5) equation: 



(2y-10)=(3y+5)

We move all terms to the left:

(2y-10)-((3y+5))=0

We get rid of parentheses

2y-((3y+5))-10=0



We calculate terms in parentheses: -((3y+5)), so:

(3y+5)

We get rid of parentheses

3y+5

Back to the equation:

-(3y+5)



We get rid of parentheses

2y-3y-5-10=0

We add all the numbers together, and all the variables

-1y-15=0

We move all terms containing y to the left, all other terms to the right

-y=15

y=15/-1

y=-15

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