(2y-10(y+1)+5)+20=30

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Solution for (2y-10(y+1)+5)+20=30 equation: 



(2y-10(y+1)+5)+20=30

We move all terms to the left:

(2y-10(y+1)+5)+20-(30)=0

We add all the numbers together, and all the variables

(2y-10(y+1)+5)-10=0



We calculate terms in parentheses: +(2y-10(y+1)+5), so:

2y-10(y+1)+5

We multiply parentheses

2y-10y-10+5

We add all the numbers together, and all the variables

-8y-5

Back to the equation:

+(-8y-5)



We get rid of parentheses

-8y-5-10=0

We add all the numbers together, and all the variables

-8y-15=0

We move all terms containing y to the left, all other terms to the right

-8y=15

y=15/-8

y=-1+7/8

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