(2y-1)/3=(y+2)/4

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Solution for (2y-1)/3=(y+2)/4 equation: 



(2y-1)/3=(y+2)/4

We move all terms to the left:

(2y-1)/3-((y+2)/4)=0

We calculate fractions


2y/()+(-((y+2)*3)/()=0



We calculate terms in parentheses: +(-((y+2)*3)/(), so:

-((y+2)*3)/(

We multiply all the terms by the denominator


-((y+2)*3)



We calculate terms in parentheses: -((y+2)*3), so:

(y+2)*3

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

-3y-6

Back to the equation:

+(-3y-6)



We get rid of parentheses

2y/()-3y-6=0

We multiply all the terms by the denominator


2y-3y*()-6*()=0

We add all the numbers together, and all the variables

2y-3y*()=0

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