(2y+7)=(3y-1)

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Solution for (2y+7)=(3y-1) equation: 



(2y+7)=(3y-1)

We move all terms to the left:

(2y+7)-((3y-1))=0

We get rid of parentheses

2y-((3y-1))+7=0



We calculate terms in parentheses: -((3y-1)), so:

(3y-1)

We get rid of parentheses

3y-1

Back to the equation:

-(3y-1)



We get rid of parentheses

2y-3y+1+7=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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