(2y+7)(4y+29)=0

Solution for (2y+7)(4y+29)=0 equation:

(2y+7)(4y+29)=0

We multiply parentheses ..

(+8y^2+58y+28y+203)=0

We get rid of parentheses

8y^2+58y+28y+203=0

We add all the numbers together, and all the variables

8y^2+86y+203=0

a = 8; b = 86; c = +203;
Δ = b2-4ac
Δ = 862-4·8·203
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-30}{2*8}=\frac{-116}{16}
=-7+1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+30}{2*8}=\frac{-56}{16}
=-3+1/2
$