(2y+62)=(8y+72)

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Solution for (2y+62)=(8y+72) equation: 



(2y+62)=(8y+72)

We move all terms to the left:

(2y+62)-((8y+72))=0

We get rid of parentheses

2y-((8y+72))+62=0



We calculate terms in parentheses: -((8y+72)), so:

(8y+72)

We get rid of parentheses

8y+72

Back to the equation:

-(8y+72)



We get rid of parentheses

2y-8y-72+62=0

We add all the numbers together, and all the variables

-6y-10=0

We move all terms containing y to the left, all other terms to the right

-6y=10

y=10/-6

y=-1+2/3

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