(2y+50)=(3y+20)

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Solution for (2y+50)=(3y+20) equation: 



(2y+50)=(3y+20)

We move all terms to the left:

(2y+50)-((3y+20))=0

We get rid of parentheses

2y-((3y+20))+50=0



We calculate terms in parentheses: -((3y+20)), so:

(3y+20)

We get rid of parentheses

3y+20

Back to the equation:

-(3y+20)



We get rid of parentheses

2y-3y-20+50=0

We add all the numbers together, and all the variables

-1y+30=0

We move all terms containing y to the left, all other terms to the right

-y=-30

y=-30/-1

y=+30

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