(2y+5)=(3y-20)

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Solution for (2y+5)=(3y-20) equation: 



(2y+5)=(3y-20)

We move all terms to the left:

(2y+5)-((3y-20))=0

We get rid of parentheses

2y-((3y-20))+5=0



We calculate terms in parentheses: -((3y-20)), so:

(3y-20)

We get rid of parentheses

3y-20

Back to the equation:

-(3y-20)



We get rid of parentheses

2y-3y+20+5=0

We add all the numbers together, and all the variables

-1y+25=0

We move all terms containing y to the left, all other terms to the right

-y=-25

y=-25/-1

y=+25

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