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(2y+5)/(y+4)=1
We move all terms to the left:
(2y+5)/(y+4)-(1)=0
Domain of the equation: (y+4)!=0We multiply all the terms by the denominator
We move all terms containing y to the left, all other terms to the right
y!=-4
y∈R
(2y+5)-1*(y+4)=0
We get rid of parentheses
2y-1*(y+4)+5=0
We move all terms containing y to the left, all other terms to the right
2y-1*(y+4)=-5
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