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(2y+4)/(y-3)=2/3
We move all terms to the left:
(2y+4)/(y-3)-(2/3)=0
Domain of the equation: (y-3)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
y!=3
y∈R
(2y+4)/(y-3)-(+2/3)=0
We get rid of parentheses
(2y+4)/(y-3)-2/3=0
We calculate fractions
(6y+12)/(3y-9)+(-2y+6)/(3y-9)=0
We multiply all the terms by the denominator
(6y+12)+(-2y+6)=0
We get rid of parentheses
6y-2y+12+6=0
We add all the numbers together, and all the variables
4y+18=0
We move all terms containing y to the left, all other terms to the right
4y=-18
y=-18/4
y=-4+1/2
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