(2y+4)(2y-4)=

Solution for (2y+4)(2y-4)= equation:

Simplifying
(2y + 4)(2y + -4) = 0

Reorder the terms:
(4 + 2y)(2y + -4) = 0

Reorder the terms:
(4 + 2y)(-4 + 2y) = 0

Multiply (4 + 2y) * (-4 + 2y)
(4(-4 + 2y) + 2y * (-4 + 2y)) = 0
((-4 * 4 + 2y * 4) + 2y * (-4 + 2y)) = 0
((-16 + 8y) + 2y * (-4 + 2y)) = 0
(-16 + 8y + (-4 * 2y + 2y * 2y)) = 0
(-16 + 8y + (-8y + 4y2)) = 0

Combine like terms: 8y + -8y = 0
(-16 + 0 + 4y2) = 0
(-16 + 4y2) = 0

Solving
-16 + 4y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4y2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4y2 = 0 + 16
4y2 = 0 + 16

Combine like terms: 0 + 16 = 16
4y2 = 16

Divide each side by '4'.
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}