(2y+32)=(3y)

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Solution for (2y+32)=(3y) equation: 



(2y+32)=(3y)

We move all terms to the left:

(2y+32)-((3y))=0

determiningTheFunctionDomain
(2y+32)-3y=0

We add all the numbers together, and all the variables

-3y+(2y+32)=0

We get rid of parentheses

-3y+2y+32=0

We add all the numbers together, and all the variables

-1y+32=0

We move all terms containing y to the left, all other terms to the right

-y=-32

y=-32/-1

y=+32

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