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(2y+3)/(y-9)=2/7
We move all terms to the left:
(2y+3)/(y-9)-(2/7)=0
Domain of the equation: (y-9)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
y!=9
y∈R
(2y+3)/(y-9)-(+2/7)=0
We get rid of parentheses
(2y+3)/(y-9)-2/7=0
We calculate fractions
(14y+21)/(7y-63)+(-2y+18)/(7y-63)=0
We multiply all the terms by the denominator
(14y+21)+(-2y+18)=0
We get rid of parentheses
14y-2y+21+18=0
We add all the numbers together, and all the variables
12y+39=0
We move all terms containing y to the left, all other terms to the right
12y=-39
y=-39/12
y=-3+1/4
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