(2y+28)=(4y+10)

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Solution for (2y+28)=(4y+10) equation:


Simplifying
(2y + 28) = (4y + 10)

Reorder the terms:
(28 + 2y) = (4y + 10)

Remove parenthesis around (28 + 2y)
28 + 2y = (4y + 10)

Reorder the terms:
28 + 2y = (10 + 4y)

Remove parenthesis around (10 + 4y)
28 + 2y = 10 + 4y

Solving
28 + 2y = 10 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
28 + 2y + -4y = 10 + 4y + -4y

Combine like terms: 2y + -4y = -2y
28 + -2y = 10 + 4y + -4y

Combine like terms: 4y + -4y = 0
28 + -2y = 10 + 0
28 + -2y = 10

Add '-28' to each side of the equation.
28 + -28 + -2y = 10 + -28

Combine like terms: 28 + -28 = 0
0 + -2y = 10 + -28
-2y = 10 + -28

Combine like terms: 10 + -28 = -18
-2y = -18

Divide each side by '-2'.
y = 9

Simplifying
y = 9

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