(2y+1)/3=(y-2)/4

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Solution for (2y+1)/3=(y-2)/4 equation: 



(2y+1)/3=(y-2)/4

We move all terms to the left:

(2y+1)/3-((y-2)/4)=0

We calculate fractions


2y/()+(-((y-2)*3)/()=0



We calculate terms in parentheses: +(-((y-2)*3)/(), so:

-((y-2)*3)/(

We multiply all the terms by the denominator


-((y-2)*3)



We calculate terms in parentheses: -((y-2)*3), so:

(y-2)*3

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

-3y+6

Back to the equation:

+(-3y+6)



We get rid of parentheses

2y/()-3y+6=0

We multiply all the terms by the denominator


2y-3y*()+6*()=0

We add all the numbers together, and all the variables

2y-3y*()=0

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