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(2y+1)/3=(y-1)/2
We move all terms to the left:
(2y+1)/3-((y-1)/2)=0
We calculate fractions
2y/()+(-((y-1)*3)/()=0
We calculate terms in parentheses: +(-((y-1)*3)/(), so:We get rid of parentheses
-((y-1)*3)/(
We multiply all the terms by the denominator
-((y-1)*3)
We calculate terms in parentheses: -((y-1)*3), so:We get rid of parentheses
(y-1)*3
We multiply parentheses
3y-3
Back to the equation:
-(3y-3)
-3y+3
Back to the equation:
+(-3y+3)
2y/()-3y+3=0
We multiply all the terms by the denominator
2y-3y*()+3*()=0
We add all the numbers together, and all the variables
2y-3y*()=0
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