(2y+1)(y-2)=

Solution for (2y+1)(y-2)= equation:

Simplifying
(2y + 1)(y + -2) = 0

Reorder the terms:
(1 + 2y)(y + -2) = 0

Reorder the terms:
(1 + 2y)(-2 + y) = 0

Multiply (1 + 2y) * (-2 + y)
(1(-2 + y) + 2y * (-2 + y)) = 0
((-2 * 1 + y * 1) + 2y * (-2 + y)) = 0
((-2 + 1y) + 2y * (-2 + y)) = 0
(-2 + 1y + (-2 * 2y + y * 2y)) = 0
(-2 + 1y + (-4y + 2y2)) = 0

Combine like terms: 1y + -4y = -3y
(-2 + -3y + 2y2) = 0

Solving
-2 + -3y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -2y)(2 + -1y) = 0

Subproblem 1
Set the factor '(-1 + -2y)' equal to zero and attempt to solve:

Simplifying
-1 + -2y = 0

Solving
-1 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2y = 0 + 1
-2y = 0 + 1

Combine like terms: 0 + 1 = 1
-2y = 1

Divide each side by '-2'.
y = -0.5

Simplifying
y = -0.5
Subproblem 2
Set the factor '(2 + -1y)' equal to zero and attempt to solve:

Simplifying
2 + -1y = 0

Solving
2 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 0 + -2
-1y = 0 + -2

Combine like terms: 0 + -2 = -2
-1y = -2

Divide each side by '-1'.
y = 2

Simplifying
y = 2
Solution
y = {-0.5, 2}