(2y+1)(2y-1)=

Solution for (2y+1)(2y-1)= equation:

Simplifying
(2y + 1)(2y + -1) = 0

Reorder the terms:
(1 + 2y)(2y + -1) = 0

Reorder the terms:
(1 + 2y)(-1 + 2y) = 0

Multiply (1 + 2y) * (-1 + 2y)
(1(-1 + 2y) + 2y * (-1 + 2y)) = 0
((-1 * 1 + 2y * 1) + 2y * (-1 + 2y)) = 0
((-1 + 2y) + 2y * (-1 + 2y)) = 0
(-1 + 2y + (-1 * 2y + 2y * 2y)) = 0
(-1 + 2y + (-2y + 4y2)) = 0

Combine like terms: 2y + -2y = 0
(-1 + 0 + 4y2) = 0
(-1 + 4y2) = 0

Solving
-1 + 4y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4y2 = 0 + 1
4y2 = 0 + 1

Combine like terms: 0 + 1 = 1
4y2 = 1

Divide each side by '4'.
y2 = 0.25

Simplifying
y2 = 0.25

Take the square root of each side:
y = {-0.5, 0.5}