(2x2+9)=(x2+34)

Solution for (2x2+9)=(x2+34) equation:

(2x^2+9)=(x2+34)

We move all terms to the left:

(2x^2+9)-((x2+34))=0

We add all the numbers together, and all the variables

-((+x^2+34))+(2x^2+9)=0

We get rid of parentheses

-((+x^2+34))+2x^2+9=0


We calculate terms in parentheses: -((+x^2+34)), so:

(+x^2+34)

We get rid of parentheses

x^2+34

Back to the equation:

-(x^2+34)


We get rid of parentheses

2x^2-x^2-34+9=0

We add all the numbers together, and all the variables

x^2-25=0

a = 1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·1·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*1}=\frac{10}{2}
=5
$