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(2x/3x+3)+6x-3(2+3)=2(5+6x)(2x-5)-5
We move all terms to the left:
(2x/3x+3)+6x-3(2+3)-(2(5+6x)(2x-5)-5)=0
Domain of the equation: 3x+3)!=0We add all the numbers together, and all the variables
x∈R
(2x/3x+3)+6x-(2(6x+5)(2x-5)-5)-35=0
We add all the numbers together, and all the variables
6x+(2x/3x+3)-(2(6x+5)(2x-5)-5)-35=0
We get rid of parentheses
6x+2x/3x-(2(6x+5)(2x-5)-5)+3-35=0
We multiply parentheses ..
-(2(+12x^2-30x+10x-25)-5)+6x+2x/3x+3-35=0
We multiply all the terms by the denominator
-((2(+12x^2-30x+10x-25)-5))*3x+6x*3x+2x+3*3x-35*3x=0
We add all the numbers together, and all the variables
-((2(+12x^2-30x+10x-25)-5))*3x+2x+6x*3x+3*3x-35*3x=0
Wy multiply elements
-((2(+12x^2-30x+10x-25)-5))*3x+18x^2+2x+9x-105x=0
We add all the numbers together, and all the variables
18x^2-((2(+12x^2-30x+10x-25)-5))*3x-94x=0
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