(2x/3)+(x/2)=(4/3)

Solution for (2x/3)+(x/2)=(4/3) equation:

(2x/3)+(x/2)=(4/3)

We move all terms to the left:

(2x/3)+(x/2)-((4/3))=0

We add all the numbers together, and all the variables

(+2x/3)+(+x/2)-((+4/3))=0

We get rid of parentheses

2x/3+x/2-((+4/3))=0

We calculate fractions


27x^2/()+4x/()+()/()=0

We add all the numbers together, and all the variables

27x^2/()+4x/()+1=0

We multiply all the terms by the denominator


27x^2+4x+1*()=0

We add all the numbers together, and all the variables

27x^2+4x=0

a = 27; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·27·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*27}=\frac{-8}{54}
=-4/27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*27}=\frac{0}{54}
=0
$