(2x-y)/2=(1-y)/3

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Solution for (2x-y)/2=(1-y)/3 equation: 


x in (-oo:+oo)

(2*x-y)/2 = (1-y)/3 // - (1-y)/3

(2*x-y)/2-((1-y)/3) = 0

(2*x-y)/2+(-1*(1-y))/3 = 0

(3*(2*x-y))/(2*3)+(-1*2*(1-y))/(2*3) = 0

3*(2*x-y)-1*2*(1-y) = 0

6*x-y-2 = 0

(6*x-y-2)/(2*3) = 0

(6*x-y-2)/(2*3) = 0 // * 2*3

6*x-y-2 = 0

6*x-y-2 = 0 // + -y-2

6*x = -(-y-2) // : 6

x = (-(-y-2))/6

x = (y+2)/6

x = (y+2)/6

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