(2x-8)+(3x+20)+(7x-10)=180

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Solution for (2x-8)+(3x+20)+(7x-10)=180 equation: 



(2x-8)+(3x+20)+(7x-10)=180

We move all terms to the left:

(2x-8)+(3x+20)+(7x-10)-(180)=0

We get rid of parentheses

2x+3x+7x-8+20-10-180=0

We add all the numbers together, and all the variables

12x-178=0

We move all terms containing x to the left, all other terms to the right

12x=178

x=178/12

x=14+5/6

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