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(2x-8)(3x-21)=0
We multiply parentheses ..
(+6x^2-42x-24x+168)=0
We get rid of parentheses
6x^2-42x-24x+168=0
We add all the numbers together, and all the variables
6x^2-66x+168=0
a = 6; b = -66; c = +168;
Δ = b2-4ac
Δ = -662-4·6·168
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-18}{2*6}=\frac{48}{12} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+18}{2*6}=\frac{84}{12} =7 $
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