(2x-7)/4=(x-3)/3

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Solution for (2x-7)/4=(x-3)/3 equation: 



(2x-7)/4=(x-3)/3

We move all terms to the left:

(2x-7)/4-((x-3)/3)=0

We calculate fractions


2x/()+(-((x-3)*4)/()=0



We calculate terms in parentheses: +(-((x-3)*4)/(), so:

-((x-3)*4)/(

We multiply all the terms by the denominator


-((x-3)*4)



We calculate terms in parentheses: -((x-3)*4), so:

(x-3)*4

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

-4x+12

Back to the equation:

+(-4x+12)



We get rid of parentheses

2x/()-4x+12=0

We multiply all the terms by the denominator


2x-4x*()+12*()=0

We add all the numbers together, and all the variables

2x-4x*()=0

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