(2x-7)/4=(x+3)/2

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Solution for (2x-7)/4=(x+3)/2 equation: 



(2x-7)/4=(x+3)/2

We move all terms to the left:

(2x-7)/4-((x+3)/2)=0

We calculate fractions


2x/()+(-((x+3)*4)/()=0



We calculate terms in parentheses: +(-((x+3)*4)/(), so:

-((x+3)*4)/(

We multiply all the terms by the denominator


-((x+3)*4)



We calculate terms in parentheses: -((x+3)*4), so:

(x+3)*4

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

-4x-12

Back to the equation:

+(-4x-12)



We get rid of parentheses

2x/()-4x-12=0

We multiply all the terms by the denominator


2x-4x*()-12*()=0

We add all the numbers together, and all the variables

2x-4x*()=0

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