(2x-7)-3(x+2)=4(x+3)+2(x-9)

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Solution for (2x-7)-3(x+2)=4(x+3)+2(x-9) equation: 



(2x-7)-3(x+2)=4(x+3)+2(x-9)

We move all terms to the left:

(2x-7)-3(x+2)-(4(x+3)+2(x-9))=0

We multiply parentheses

(2x-7)-3x-(4(x+3)+2(x-9))-6=0

We get rid of parentheses

2x-3x-(4(x+3)+2(x-9))-7-6=0



We calculate terms in parentheses: -(4(x+3)+2(x-9)), so:

4(x+3)+2(x-9)

We multiply parentheses

4x+2x+12-18

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

-1x-(6x-6)-13=0

We get rid of parentheses

-1x-6x+6-13=0

We add all the numbers together, and all the variables

-7x-7=0

We move all terms containing x to the left, all other terms to the right

-7x=7

x=7/-7

x=-1

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