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(2x-7)-(3x+2)=5(x-3)
We move all terms to the left:
(2x-7)-(3x+2)-(5(x-3))=0
We get rid of parentheses
2x-3x-(5(x-3))-7-2=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
-1x-(5x-15)-9=0
We get rid of parentheses
-1x-5x+15-9=0
We add all the numbers together, and all the variables
-6x+6=0
We move all terms containing x to the left, all other terms to the right
-6x=-6
x=-6/-6
x=1
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